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Simplifying 15C2 + 29C + -14 = 0 Reorder the terms: -14 + 29C + 15C2 = 0 Solving -14 + 29C + 15C2 = 0 Solving for variable 'C'. Factor a trinomial. (-7 + -3C)(2 + -5C) = 0Subproblem 1
Set the factor '(-7 + -3C)' equal to zero and attempt to solve: Simplifying -7 + -3C = 0 Solving -7 + -3C = 0 Move all terms containing C to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -3C = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -3C = 0 + 7 -3C = 0 + 7 Combine like terms: 0 + 7 = 7 -3C = 7 Divide each side by '-3'. C = -2.333333333 Simplifying C = -2.333333333Subproblem 2
Set the factor '(2 + -5C)' equal to zero and attempt to solve: Simplifying 2 + -5C = 0 Solving 2 + -5C = 0 Move all terms containing C to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -5C = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -5C = 0 + -2 -5C = 0 + -2 Combine like terms: 0 + -2 = -2 -5C = -2 Divide each side by '-5'. C = 0.4 Simplifying C = 0.4Solution
C = {-2.333333333, 0.4}
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